Question

prove that the tangents drawn from end of the diameter of a circle are paralle​

Answer 1

HERE IS UR ANSWER DEAR ✪ ω ✪

ATQ,

PQ AND RS ARE THE TWO TANGENTS TO THE CIRCLE(O,r) AT A AND B RESPECTIVELY.

∴PAB=QAB=RBA=SBA=90°⇒(tangents ⊥ radius)

∵QAB=RBA=90

 PAB=SBA=90

BUT THEY ARE ALTERNATE INTERIOR ANGLES

HENCE PQ║RS(BY ALTERNATE INTERIOR ANGLES AXIOM)

NOTE : IF ALTERNATE INTERIOR ANGLES ARE EQUAL THEN THE LINES ARE PARALLEL❣¯\_(ツ)_/¯

HOPE IT HELPS YOU(☞ﾟヮﾟ)☞