Question

prove that the zero of the polynomial p(x) =ax^2 - 3(a-1)x-1,then find the value of A​

Answer 1

Answer:

p(x) = ax^2 - 3(a-1) x-1

1 is the zero if polynomial p(x)

p(1) = 0

a1^2 - 3(a-1) x-1 = 0

a - 3a + 3 -1 = 0

- 2a + 2 = 0

a = -2/-2

a =2

Answer 2

The value of A = 2.

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