Question

Prove that there is no natural number for which 16^n ends with the digit zero. 

Answer 1

16^n 
Let us consider n=1 
then we get 16^1=16
if n=2 then 16^2=256
if n=3 then 16^3= 4096
if n=3 then 16^4 = 65536
.......................
from this we can say that 16^n  
for any value of the 'n'  the number ends with 6 but not with zero

Answer 2

if we take n=1 then it will be 16 
n=2 it will be 256 
n=3 it we be 4096 
proves that 16 ^ any number will have 6 in units place not 0