Prove that there is no natural number for which 16^n ends with the digit zero.
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16^n
Let us consider n=1
then we get 16^1=16
if n=2 then 16^2=256
if n=3 then 16^3= 4096
if n=3 then 16^4 = 65536
.......................
from this we can say that 16^n
for any value of the 'n' the number ends with 6 but not with zero
Let us consider n=1
then we get 16^1=16
if n=2 then 16^2=256
if n=3 then 16^3= 4096
if n=3 then 16^4 = 65536
.......................
from this we can say that 16^n
for any value of the 'n' the number ends with 6 but not with zero
Answered by
0
if we take n=1 then it will be 16
n=2 it will be 256
n=3 it we be 4096
proves that 16 ^ any number will have 6 in units place not 0
n=2 it will be 256
n=3 it we be 4096
proves that 16 ^ any number will have 6 in units place not 0
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Yeah u doo!
thanks
but what that means
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