Question

Prove that there is no natural number for which 4^n ends with a zero.

Answer 1

4=2×2
The prime factorization of 4 does not contain 2 and 5 . To end with the digit zero the number should be in the form 2^m×5^n. But 4 does not contain 5.
Hope this helps u

Answer 2

4is a factor of 2 but to end in zero it should have a factor in the form of 2^m5^n