Prove that there is no natural number for which 4^n ends with a zero.
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4=2×2
The prime factorization of 4 does not contain 2 and 5 . To end with the digit zero the number should be in the form 2^m×5^n. But 4 does not contain 5.
Hope this helps u
The prime factorization of 4 does not contain 2 and 5 . To end with the digit zero the number should be in the form 2^m×5^n. But 4 does not contain 5.
Hope this helps u
thisissahilgagpbhydr:
Thanks for the answer and also the extra info!
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4is a factor of 2 but to end in zero it should have a factor in the form of 2^m5^n
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