Question

prove that this problem​

Answer 1

$lhs = \frac{ {sin}^{3 }0 + {cos}^{3} 0 }{sin0 + cos0} \\ \\ = \frac{(sin0 + cos0)( {sin}^{2}0 + {cos}^{2}0 - sin0.cos0) }{(sin0 + cos0)} \\ \\ = {sin}^{2}0 + {cos}^{2}0 - sin0.cos0 \\ \\ = 1 - sin0.cos0 \\ \\ = rhs$

Hope it's helpful

Answer 2

Answer:

Ok I'll be your friend ✌️✌️

so your intro please..