Question

prove that total mechanical energy of a free falling object remains always constant​

Answer 1

the body is at position B. the body has moved x distance from A.

acco. to B

v2=u2+ 2as

v2=0+2ax

KE=1/2mv2

1/2m×2gx

KE=mgx

Ep=mg(h-x)

total energy

Ep+Ek=mg

mgh-mgx+mgx=mgh

if body reaches position c

v2=u2+2as

v2=2gh

total energy at c

E=Ep+Ek

=0+mgh

mgh

it energy of body remain constant