prove that triangle ABC is a right angled at A if AB =2n+1,AC=2n (n+1) and BC = 2n(n+1)+1
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Answer:
nice Q
Step-by-step explanation:
2n+1+2n=2n(n+1)+1
4n+1=2n+2+1
4n-2n=2+1-1
2n=2
n=2/2
n=1
AB=2n+1
2*1+1
3
AC=2n
2*1
2
BC=2n(n+1)+1
2*1(1+1)+1
2*2+1
4+1
5
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