Question

what are the feelings of the son while father is carrying the luggage
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Answer 1

Answer:

Explanation:

Question 1 )

Given : -

mass = 20 kg

initial velocity (u) = 5 m/sec

final velocity (v) = 2 m/sec

time (t)= 1sec

Solution : -

so , from first equation of motion

v= u+ at

or, a= ( v- u) / t

a= ( 2 ms-¹ - 5 ms-¹) / 15

a= - 3 ms-²

therefore, from third equation of motion

v²- u²= 2as

= ( 2ms -1 )² - ( 5ms-¹) ²

= 2× (-3ms-²) ×5

= -21 m²s² = -6ms-²× 5

= s = 7/2 metre

therefore, we know ,

workdone= f × s

and , F = m× a

so, work = m× a× s

= 20 kg × ( -3ms-²) × 7/2m

= - 210 joules.

Hence the answer is - 210

Question ( 2 )

Given : -

v = 5m/s

K.E = 25 J

Solution : -

K.E = 1/2 mv^2

25 = 1/2 m (5)^2

25 x 2 = 25m

m = 2 kg

Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S

Now new K.E = 1/2 x 2 x 15^2

= 225 J

Answer is 225 j

Answer 2

Answer:

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