Question

prove that triangle ABC is congruence to triangle DCB,if AC=DB and angle A=angleD=90°

Answer 1

the triangles are congruent by
RHS

Answer 2

$In \: \triangle ABC \:and \:\triangle DCB$

$\angle A = \angle D = 90 \: degree ( given )\\\blue {( Right \:angle ) }$

$BC = CB \: \blue{( Hypotenuse )}$

$AC = DB \: ( Side )$

$\triangle ABC \cong \triangle DBC$

$\pink { ( RHS \: Congruence )}$

$\underline{ \blue { RHS \: congruence \:rule:}}$

If in two right triangles the hypotenuse and one side of one triangle are equal to the hypotenuse and corresponding side of the other triangle , then the two triangles are congruent .

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