Question

prove that triangle PQR congruent to triangle PSR and also prove that QR=PS ​

Answer 1

In ∆PQR, ∆PSR

ANGLE PQR= ANGLE PSR (EACH OF 90°)

PR=PR (COMMON)

PS=PQ (GIVEN)

.'. ∆PQR =~ ∆PSR BY SIDE ANGLE SIDE CONGRUENCY(SAS) RULE

QR=RS BY CPCT