Question

prove that Triangles lying on the same base or equal bases and between same parallels are equal in area with an attachment plz.

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answer plz

Answer 1

Step-by-step explanation:

given ∆ ABC and ∆dbc having a common base bc and between the // line bc and ad

to prove :- ar. of the ∆abc = ar. of the ∆dbc

construction: ad is produced both ways to point p and q such that pbcc and abcq are //gram.

proof:-

in //gram pbcd, bd is the diagonal

ar. of the ∆ pbd= ar. of the ∆dbc

(diagonal of //gram divides the //gram into two equal ∆)

therefore, ar. of ∆dbc= 1/2 of the ar. of //gram pbcd-----1

similarly in // abcq, ac is the diagonal,

ar. of the ∆ abc= 1/2 of the ar. of //gram abcq----2

but ar. of the //gram pbcd= ar. of the //gram abcq

(theorem:-a //gram on the same base and between two parallel line are equal)

from 1 and 2, we have ,

∆dbc=∆abc

hence proved.

hope this help...

Answer 2

Answer:

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