Prove that two tangents drawn from an external point to a circle are of equal length.
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To prove PT=QTPT=QTProof: Consider the triangle OPTOPT and OQTOQT.OP=OQOP=OQ∠OPT=∠OQT=90∘∠OPT=∠OQT=90∘OT=OTOT=OT (common side)Hence by RHS the triangles are equal.Hence PT=QTPT=QTHence Proved.
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To prove PT=QT
Proof: Consider the triangle OPT and OQT.
OP=OQ
∠OPT=∠OQT=90∘
OT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QT
Hence Proved.
Proof: Consider the triangle OPT and OQT.
OP=OQ
∠OPT=∠OQT=90∘
OT=OT (common side)
Hence by RHS the triangles are equal.
Hence PT=QT
Hence Proved.
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