Question

Prove that under root 7 is irrational number

Answer 1

Here 7 divides b² so for 7 divides b. Here we find 7 is common which divide both a and b but this is contradiction because a and b are co prime they don't have common factor other than 1. So for our assumption is wrong. Hence √7 is irrational.

Answer 2

Answer:

7 is irrational number

Step-by-step explanation:

√7

=2√3

= 2×1.7320.....

it is not a terminating Or non terminating number

so it s irrational number

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