prove that under root 7 is irrational number class 10
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Let √7 is a rational number equal to a/b ( where a and b are co-primes ).
⇒ √7 = a/b
Squaring both sides,
⇒ ( √7 )² = ( a/b )²
⇒ 7 = a²/b²
⇒ 7b² = a²
Since 7 is a factor of a², so it will be also factor of a.
Now , assume ( a = 7m ).
⇒ 7b² = ( 7m )²
⇒ 7b² = 49m²
⇒ b² = 49m² / 7
⇒ b² = 7m²
Since 7 is a factor of b², so it will be also factor of b.
So, our assumption that a and b are co-primes is wrong because they have 7 as a factor.It means our assumption that √7 is a rational number is wrong.
Hence, √7 is not a rational number that is it is a irrational number.
⇒ √7 = a/b
Squaring both sides,
⇒ ( √7 )² = ( a/b )²
⇒ 7 = a²/b²
⇒ 7b² = a²
Since 7 is a factor of a², so it will be also factor of a.
Now , assume ( a = 7m ).
⇒ 7b² = ( 7m )²
⇒ 7b² = 49m²
⇒ b² = 49m² / 7
⇒ b² = 7m²
Since 7 is a factor of b², so it will be also factor of b.
So, our assumption that a and b are co-primes is wrong because they have 7 as a factor.It means our assumption that √7 is a rational number is wrong.
Hence, √7 is not a rational number that is it is a irrational number.
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