prove that, v^2 = u^2+2as
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Answered by
5
v = u + at
⇒ v² = (u+at)²
⇒ v² = u²+2u*at+a²t²
⇒v²=u²+2a* (ut+1/2at²)
⇒v² = u²+2as [∵s = ut+1/2at²]
∴ v² = u²+2as (is proved)
Answered by
1
Explanation:
v^2=(u+at)^2
v^2=u^2+2u* at +a^2t^2
v^2=u^2+2a*(ut + 1/2 at^2)
v^2=u^2+2as [s=ut+1/2at^2]
v^2=u^2+2as
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