Question

prove that very urgent​

Answer 1

Answer:

formula used here,

$\sin( \alpha ) - \sin( \beta ) = 2 \cos( \frac{ \alpha + \beta }{2} ) \sin( \frac{ \alpha - \beta }{2} ) \\ \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\ \cos( \alpha ) + \cos( \beta) = 2 \cos( \frac{ \alpha + \beta }{2} ) \cos( \frac{ \alpha - \beta }{2} )$