prove that :
weight of the object on the moon = (1/6)×its weight on the earth
Answers
We are asked to prove that, weight of the object on the moon = (1/6) × its weight on the earth.
~ Firstly let us revise the below mentioned criteria properly to solve this question!
Celestial bodies: Moon and earth respectively.
Mass of Moon and earth respectively: 7.36 × 10²² and 5.98 × 10²⁴
Radius of Moon and Earth respectively = 1.74 × 10⁶ and 6.37 × 10⁶
Now let us assume that the mass of an object becames m. Let's the weight of the similar object on moon becames and let let mass of moom becames and let's the radius of moon becames Now let the weight of same object on earth becames Let the mass of earth is and the radius as
Firstly let equation first as the formula of gravity that is given below:
Now according to the universal law of gravitation the weight of the object on the surface of moon will be
Now combining equation first and second we get the following results:
Now we have to use our creteria and have to imply values from this in equation third, let's imply and further solve!
Now we have to divide Equation 4 (a) with Equation 4 (b) and further solve!
Therefore, proved that weight of the object on the moon = (1/6) × its weight on the earth.
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Important while solving this question: Don't forget law of exponents. Use them carefully, any single mistake will led to wrong way to answer.