Prove that work done is equal to P Delta V
Answers
Answered by
12
Answer:
In a quasistatic process (reversible), the difference between the external pressure and the internal pressure is infinitesimal for each infinitesimal change in the volume of the system.
Pext=Pint±dPPext=Pint±dP,
As you know that the term for work in terms of pressure is given by, dW=PdVdW=PdV. This means that work obtained will be maximum if the pressure is maximum for each infinitesimal change in volume.
In a reversible process, the work done in each step obtained is maximum since the external pressure in only infinitesimally greater (or smaller) than the internal pressure.
Explanation:
यह आपकी मदद कर सकता है शायद धन्यवाद
Attachments:
![](https://hi-static.z-dn.net/files/d36/d083236ec6e776bb0345e59489b5012e.jpg)
Similar questions