Question

prove that x^2 +25 has no real zeroes.

Answer 1

X^2 +25 =0 Compare this equation with ax^2+bx +c =0 now a=1 ,b=0 ,c= 25 Now find D If D>0 roots are real And if D < 0 roots are not real D = b^2-4ac = 0-4*1*25=-100 >0 so the roots are not real