Question

prove that x+2 is a factor of p(x)=2x³-4x²+5x+42
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Answer 1

Answer:

p(x)=2x³-4x²+5x+42

x+2 = 0

X = -2

p(x) = 2 (-2)^3 - 4 (-2)^2 + 5(-2) + 42

= 2 (-8) - 4 (4) - 10 + 42

= -16 - 16 - 10 + 42

= -42 + 42

= 0

hence x+2 is a factor of p(x)=2x³-4x²+5x+42

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Answer 2

Step-by-step explanation:

Let us the value of p(x) = x+2

Thus, x+2 = 0

x = -2

After putting the value of x in the equation, we will get

2x³-4x²+5x+42

= 2(-2)³-4(-2)²+5(-2)+42

= -16-16-10+42 = 0

Therefore, x+2 is a factor of 2x³-4x²+5x+42...

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