Question

prove that (x-y) (x+y) + (y-z) (y+z) (z-x) ( z+x) = 0
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Answer 1

Step-by-step explanation:

check attachment

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Answer 2

Answer:

SEE BELOW

Step-by-step explanation:

(x+y)(x-y)(y+z)(y-z)+(z-x)(z+x)=0(given).

Using:- (a+b)(a-b) = a²-b²

So, x²-y²+y²-z²+z²-x²=0

0 = 0

Hence, proved.