Prove that x²-x is divisible by 2 for all the integer x.
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Answered by
2
so x²- x
= x(x - 1)
so we know every even number can be divided by 2
if we put any value
then either of the x or x -1 will be even
that is if we take 2 then
2(2 -1) is divisible by 2
if we take 3
3(3 -1)
= 3 (2)
is divisible by 2 so proved
= x(x - 1)
so we know every even number can be divided by 2
if we put any value
then either of the x or x -1 will be even
that is if we take 2 then
2(2 -1) is divisible by 2
if we take 3
3(3 -1)
= 3 (2)
is divisible by 2 so proved
Anonymous:
hope it helps
Answered by
1
so given x²- x
= x(x - 1)
so we know any even number can be divided by 2
if we put any value
then either of the x or x -1 will be even
that is
if we take 2
then
2(2 -1) is divisible by 2
if we take 3
3(3 -1)
= 3 (2) so divisible by 2
if we take 4
= 4(4-1) so divisible by 2
if we take 5
= 5(5 - 1)
= 5(4)
is divisible by 2 so proved
= x(x - 1)
so we know any even number can be divided by 2
if we put any value
then either of the x or x -1 will be even
that is
if we take 2
then
2(2 -1) is divisible by 2
if we take 3
3(3 -1)
= 3 (2) so divisible by 2
if we take 4
= 4(4-1) so divisible by 2
if we take 5
= 5(5 - 1)
= 5(4)
is divisible by 2 so proved
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