Question

prove that x³ + y³ +z²-3xyz=(x+y+z)(x²+y²+z²-XY-YZ-ZX).hence find value of x³+y³+z³ if x+y+z=0​

Answer 1

Answer:

x cube plus y cube + Z cube - 3 xyz is equal to (X + Y + Z)( x square + Y square + Z Square - x y - Y Z - z x)

x cube plus y cube plus z cube minus 3xyz =0(x square plus y square plus z square -xy -yz-zx)

x cube plus y cube plus z cube -3xyz=0

x cube plus y cube plus z cube =3xyz