prove that y-y1 = y2 - y1 upon y2 -y1 (x - x1) )
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We know that equation of the line which passes through the point (x1, y1) and has slope m is given by y-y1=m(x-x1)
We could start with this equation, as we atleast know that the line passes through (x1, y1).
But we have no idea about the slope. Instead, we’ve been another point (x2, y2), through which the line passes.
That means, the coordinates (x2, y2) must satisfy the above equation. That is, y2-y1=m(x2-x1), or m=(y2-y1)/(x2-x1)
And that’s all. The required equation is y-y1=y2−y1x2−x1(x-x1)
The slope of the line joining two points, (x1, y1) and (x2, y2) is given by (y2-y1)/(x2-x1).
We could start with this equation, as we atleast know that the line passes through (x1, y1).
But we have no idea about the slope. Instead, we’ve been another point (x2, y2), through which the line passes.
That means, the coordinates (x2, y2) must satisfy the above equation. That is, y2-y1=m(x2-x1), or m=(y2-y1)/(x2-x1)
And that’s all. The required equation is y-y1=y2−y1x2−x1(x-x1)
The slope of the line joining two points, (x1, y1) and (x2, y2) is given by (y2-y1)/(x2-x1).
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