Prove thatt 8ae²=3ac²+5ad² when abc is tridected by dand e
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Join AD AND AE.
keep each part as x.
therefore,BD=x
DE=2x
CE=3x
construct a perpendicular from a
use pythagoras everywhere
first get AE square and multiply the whole equation by 8.
then get AC square and multiply the whole equation by 3
then get AD square and multiply the whole equation by 5.
ADD 3AC square and 5ADsquare
subtract the result by 8AE square
u will get the ans.
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