PROVE THE ABOVE EQUATION.
AND PLEASE ANSWER PROPERLY!!
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we know that
tan (90-A) = cotA
cot(90-A) = tanA
cosec(90-A) = sec A
sin (90 -A) = cosA
sec^2 A - 1 = tan^2 A
this also gives sec^2A - tan^2 A = 1
cosec^2 A - 1 = cot^2 A
this also gives
cosec^2 A - cot^2 A = 1, or
1 + cot^2 A = cosec^2 A
now our problems
I) cosec^2A + tan^2 (90 - A) = 2tan^2(90-A) + 1
LHS = cosec^2 A + tan^2 (90-A)
cosec^2 A + cot^2A
1 + cot^2 A + cot^2 A
2 cot^2 A + 1
2 tan^2(90-A) + 1
RHS
i
try to solve other two in similar manner
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