Question

PROVE THE ABOVE EQUATION.
AND PLEASE ANSWER PROPERLY!!

If u don't know the answer then just leave it and don't put unwanted statements..........
please...........​​!!​

Answer 1

SOLUTION :-

sin(x+y)/sin(x-y) =(a+b)/(a-b)

applying componendo and dividendo

$\frac{sin(x + y) + sin(x - y)}{sin(x + y) - sin(x - y)} = \frac{a + b + a - b}{a + b - a + b}$

$\frac{2 \: sinx \: cosy}{2 \: cosx \: siny} = \frac{a}{b}$

$\frac{tanx}{tany} = \frac{a}{b}$