Question

.Prove the electric field on the surface of conductor
is

Q/2​

Answer 1

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HERE IS YOUR ANSWER:-

Show that the electric field at the surface of a charged conductor is given by →E=σε0ˆn , where σ is the surface charge density and ˆn is a unit vector normal to the surface in the outward direction . Solution : Electric field at a point on the surface of charged conductor , E=14πε0QR2 .

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