Q2.The value of 2^0 +7^0 is *
1 point
3
2
4
Answers
so sorry man. your questions are not clear. from next time pls cross check your questions befor posting them. it's just makes it easy for us to answer. thank you
Step-by-step explanation:
Evaluate:
(i) 3-2 (ii) (-4)-2 (iii) (1/2)-5
Answer:
(i) 3-2 = 1/32 = 1/9 [a-m = 1/ am]
(ii) (-4)-2 = 1/42 = 1/16 [a-m = 1/ am]
(iii) (1/2)-5 = (2/1)5 = 25 = 32 [a-m = 1/ am]
Question 2:
Simplify and express the result in power notation with positive exponent:
(i) (-4)5 ÷ (-4)8 (ii) (1/23)2 (iii) (-3)4 * (5/3)4 (iv) (3-7 * 3-10) * 35
(v) 2-3 * (-7)3
Answer:
(i) (-4)5 ÷ (-4)8 = (-4)5-8 [am ÷ an = am-n]
= (-4)-3
= 1/(-4)3 [a-m = 1/ am]
= -1/64
(ii) (1/23)2 = 12/(23)2 [(a/b)m = am/bm]
= 1/ 23*2 [(am)n = am*n]
= 1/26
= 1/64
(iii) (-3)4 * (5/3)4 = (-3)4 * (54/34 ) [(a/b)m = am/bm]
= (3)4 * (54/34 ) [(-a)m = am when m is an even number]
= (3)4-4 * 54
= 54
(iv) (3-7 * 3-10) * 35 = 3-7-10+5 [am * an = am+n]
= 3-17+5
= 3-12
= 1/312 [a-m = 1/ am]
(v) 2-3 * (-7)-3 = 1/23 * 1/(-7)-3 [a-m = 1/ am]
= 1/{(-7)3 * 23 }
= 1/(-7 * 2)3 [am * bm = (a * b)m]
= 1/(-14)3
= -1/(14)3 [(-a)m = -am when m is an odd number]