Prove the following (2a+3b)^2 + (2a-3b)^2= 8a^2+18b^2
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Answer:
(2a+3b)²+(2a-3b)² =(2a)²+(3b)²+12ab+(2a)²+(3b)²-12ab
=4a²+9b²+4a²+9b²
=8a²+18b²
Hence proved...
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