Prove the following
(a) sin(-110°). + tan(290°)/cot(200) +cos (340)
(b) sin(0-270)/cos( 0-360) +sec(270+0)/cosec(180+0) +cot(90+0)/tan(360+0)
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0
Answer:
Correct option is
A .cos θ
Step-by-step explanation:
cos(90
0
+θ)=−sinθ,sec(270
0
−θ)=cosecθ,sin(180
0
+θ)=−sinθ
∴ Given exp. =
(−cosecθ)(−sinθ)tanθ
(−sinθ)(cosecθ)(−sinθ)
=cosθ.
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