Prove the following are irrational
(1) 1/√2
(2) √3+√5
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1) 1/√2=p/q (assume that it is a rational )
√2=Q/p ... So it is irrational......
2) √3+√5=p/q (assume that it is a rational )
squaring on both sides
(√3+√5)*2=(p/q)*2
3+5+2√3*√5=p*2/q*2
2√15=p*2/q*2-8
√15=p2-8q2/2q*2 hence it is irrational
√2=Q/p ... So it is irrational......
2) √3+√5=p/q (assume that it is a rational )
squaring on both sides
(√3+√5)*2=(p/q)*2
3+5+2√3*√5=p*2/q*2
2√15=p*2/q*2-8
√15=p2-8q2/2q*2 hence it is irrational
maths786:
nice explanation :)
Answered by
1
They both are irrational because all non-square Numbers are considered as irrational numbers
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