Prove the following identitie:
If x= a seco+b tan 0 and
y = a tano + b seco, prove that
x² -y² = a² -b².
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according to question
x=acos∅+btan∅
x^2=a^2cos^2∅+b^2tan^2∅+ 2absin∅/cos^2∅
y^=a^2tan^2∅+b^2sec^2ⁿ+2absin∅/cos^2∅
subtracting this,u will get
x^2-y^2=a^2-b^2
hope it helps you
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