prove the following identity : if x = a sec theta, y = b tan theta, prove that a^2/x^2-b^2/y^2=1
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x=a sec@ =>(x/a)=sec @..(I)
y=b tan @ =>(y/b)=tan @. (ii)
Also, sec ^2@ - tan ^2 @=1 ( Identity (
So, from eq(I) and (ii)
(x/a)^2 - (y/b)^2 =1
Hope it helps.
y=b tan @ =>(y/b)=tan @. (ii)
Also, sec ^2@ - tan ^2 @=1 ( Identity (
So, from eq(I) and (ii)
(x/a)^2 - (y/b)^2 =1
Hope it helps.
sarabjeet1010pp4n1ic:
nice
We have to prove a^2/x^2- b^2/y^2 this.... Not
(x/a)^2 - (y/b)^2 =1 This
(x/a)^2 - (y/b)^2 =1 This
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