Prove the following identity of question number 5 (i)
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1/(tanA+cotA)=sinAcosA
LHS =1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/sinAcosA
=sinAcosA
RHS
LHS =1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/sinAcosA
=sinAcosA
RHS
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