Prove the following identity of question number 5 (i)
Attachments:
Answers
Answered by
0
1/(tanA+cotA)=sinAcosA
LHS =1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/sinAcosA
=sinAcosA
RHS
LHS =1/(sinA/cosA+cosA/sinA)
=1/(sin^2A+cos^2A)/sinAcosA
=sinAcosA
RHS
Similar questions