Question

prove the following quickly please

Answer 1

hey mate,

here is your answer,

x[y×z-(z-x)(y+x)]-(y-z)[(x+z)z-(z-x)(x-y)]+(z+y)[(x+z)(y+x)-y(x-y)]=0

x[yz-zy+zx-xy-x^2]-(y-z)[xz-z^2-zx-zy-x^2+xy]+(z+y)[xy+x^2+zy+zx-yx+y^2]=0

x(zx-xy-x^2)-(y-z)(-z^2-zy-x^2+xy)+(z+y)(x^2+zx)=0

zx^2-yx^2-x^3-zy^2-yx^2+xy^2+z^3+zx^2-xyz+zx^2+xz^2+yx^2+xyz=0

(x^3+y^3+z^3)=0

(x+y+z)(x^2+y^2+z^2)

LHS=RHS

hence proved