Question

Prove the following (seco + tano) (1 - sino) = coso​

Answer 1

Answer:

0 = theta

Step-by-step explanation:

$=(sec0 +tan0) (1-sin0 )\\=(\frac{1}{cos0}+\frac{sin0}{cos0})(1-sin0)\\=(\frac{1+sin0}{cos0})(1-sin0)\\=\frac{(1+sin0)(1-sin0)}{cos0}\\=\frac{1-sin0+sin0-sin^20}{cos0} \\=\frac{1-sin^20}{cos0}\\= \frac{cos^20}{cos0} \\=cos0$

hence, lhs=rhs proved

Answer 2

(sec0 + tan0) (1 - sin0) = coso0

( 1 + 0) ( 1 - 0) = 1

1² - 0² = 1

1 - 0 = 1

1 = 1 ■