Math, asked by tokaians, 1 year ago

Prove the following
tan ^2 x - sin ^2 x = sin ^2 x sin ^2 x

Answers

Answered by abhi178
0
LHS = tan²x - sin²x

=sin²x/cos²x - sin²x

= sin²x( 1 - cos²x)/cos²x

[use, sin²x = 1- cos²x ]

= sin²x.sin²x/cos²x

= {sin²x/cos²x}.sin²x

=tan²x.sin²x = RHS

tokaians: not clear
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