Question

find the area of an isosceles triangle whose base is 'a' and equal sides are of lenght "b'

Answer 1

we know, in isosceles triangle altitude , is bisect to base.

so, Altitude = √(side length of equal side )² - (base/2)² } = √(b² -a²/4)

now, area of isosceles triangle = 1/2 × altitude × base

= 1/2 × √(b² - a²/4) × a

= 1/4 × a × √(4b² - a²)

Answer 2

Answer:

we know, in isosceles triangle altitude , is bisect to base.

so, Altitude = √(side length of equal side )² - (base/2)² } = √(b² -a²/4)

now, area of isosceles triangle = 1/2 × altitude × base

= 1/2 × √(b² - a²/4) × a

= 1/4 × a × √(4b² - a²)