Question

The HCF of two numbers is 23 and their LCM is 1449. If one of the number is 275. Find the other.​

Answer 1

Answer:

Given, HCF=23

LCM=1449

Let the two numbers be a and b. Let a=161. We have to find b.

We know that

HCF(a,b)×LCM(a,b)=a×b

⇒23×1449=161×b

⇒23×

161

1449

=b

⇒b=23×9

∴b=207

Thus, the other number is 207.

Answer 2

Answer:

we know HCF X LCM = product of the two numbers

hcf = 23

lcm = 1449

let the numbers = 275,x

so,

275*x = 1449*23

x = 33327/275

x = 121.19

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