The HCF of two numbers is 23 and their LCM is 1449. If one of the number is 275. Find the other.
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Answered by
0
Answer:
Given, HCF=23
LCM=1449
Let the two numbers be a and b. Let a=161. We have to find b.
We know that
HCF(a,b)×LCM(a,b)=a×b
⇒23×1449=161×b
⇒23×
161
1449
=b
⇒b=23×9
∴b=207
Thus, the other number is 207.
Answered by
0
Answer:
we know HCF X LCM = product of the two numbers
hcf = 23
lcm = 1449
let the numbers = 275,x
so,
275*x = 1449*23
x = 33327/275
x = 121.19
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