Question

Prove the following theorem
Theorem: A perpendicular drawn from the centre of a circle on its chord bisects the chord.
Given : seg AB is chord of a circle with O. Seg OP / chord AB.​

Answer 1

Answer:

Let the two chords be AB and CD. Let OE be the perpendicular drawn from the centre of the circle to the chord AB. Perpendicular drawn from the centre of the circle to the chord bisects the chord. Thus, AB = CD = 24 cm as chords of a circle equidistant from the centre are congruent.