Prove the following trigonometric identities
do question number 21 and 22
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21)
sec².(1²-sin²)=sec².cos²=1/cos².cos²=1
LHS=RHS
22) sin².(cos²/sin²)+cos².(sin²/cos²)
cos²+sin²=1
LHS=RHS
sec².(1²-sin²)=sec².cos²=1/cos².cos²=1
LHS=RHS
22) sin².(cos²/sin²)+cos².(sin²/cos²)
cos²+sin²=1
LHS=RHS
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Ihope it will help u
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