Question

Prove the following trigonometric identities. $\frac{1+cosA}{sin^{2}A}=\frac{1}{1-cosA}$

Answer 1

Answer with Step-by-step explanation:

Given :  

(1 + cosA) /sin² A = 1/(1 – cosA)

LHS : (1+ cosA) /sin² A

= (1 + cosA) / (1 - cos² A)

[By using  an identity, sin²θ = (1- cos²θ) ]

= (1 + cosA) / [(1 + cosA)(1 - cos A)]

[By using identity , a² - b² = (a + b) (a - b)]

=  1/(1 – cosA)

(1 + cosA) /sin² A = 1/(1 – cosA)

L.H.S = R.H.S  

Hence Proved..

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Answer 2

Step-by-step explanation:

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