Question

x² + Kx +20, Having real
& equal roots find the value k​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The equation given is : x^2 + Kx + 20

We also know that the roots is real and equal.

Therefore,

                  a=+1 , b = K , c = +20

           

                  b^2 - 4ac = 0

               => K^2 - 4(1)(20) = 0

               => K^2 - 80 = 0

               => K^2 = 80                

               => K =  $\sqrt{80}$

                    K = 4\sqrt{5}[/tex]