Prove the formula of diagonals of cuboid (√l^2+b^2+h^2)
Answers
Answered by
0
By using vectors, Length of diagonal from O(0,0,0) to P(l,b,h) => √(l^2 + b^2 + h^2)
ayushkuma:
I can not understand your answer
Answered by
3
Length,Breath and height of Cuboid be l ,b,and h
Now length of the diagonal(d1) along floor will be = √(l^2+b^2)...................(1)
Now consider a right angled triangle in which base is the diagonal(d1) and perpendicular is the height of cuboid.
Hypotenuses = √(d1^2+ h^2) =(l^2+b^2+h^2)(from equation 1)
Hope this would have cleared you doubt.
Now length of the diagonal(d1) along floor will be = √(l^2+b^2)...................(1)
Now consider a right angled triangle in which base is the diagonal(d1) and perpendicular is the height of cuboid.
Hypotenuses = √(d1^2+ h^2) =(l^2+b^2+h^2)(from equation 1)
Hope this would have cleared you doubt.
Similar questions