Math, asked by ayushkuma, 1 year ago

Prove the formula of diagonals of cuboid (√l^2+b^2+h^2)

Answers

Answered by Blue27
0
By using vectors, Length of diagonal from O(0,0,0) to P(l,b,h) => √(l^2 + b^2 + h^2)

ayushkuma: I can not understand your answer
Answered by grvbundela008p3f6id
3
Length,Breath and height  of Cuboid be l ,b,and h 
Now length of the diagonal(d1) along floor will be = √(l^2+b^2)...................(1)
Now consider a right angled triangle in which base is the diagonal(d1) and perpendicular is the height of cuboid.
Hypotenuses = √(d1^2+ h^2) =(l^2+b^2+h^2)(from equation 1)
Hope this would have cleared you doubt.
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