prove the given question
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Step-by-step explanation:
Given :-
In ∆ABC, AD bisects interior ∠A and AE bisects exterior ∠A meeting BC at D and BC produced in E.
To prove:- BD/BE = CD/CE
Proof:-
In ∆ABC, AD bisects interior ∠A ( Given )
∴ AB/AC = BD/DC (Angle bisector theorem) .___(1)
Similarly in ∆ABC, AE bisects exterior ∠A ( Given )
∴ AB/AC = BE/CE .____(2)
Therefore, From eq. (1) and (2)
AB/AC = BD/DC = BE/CE = CD/CE
Thus, BD/BE = CD/CE
Hence proved.
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