Question

prove the given question​

Answer 1

Step-by-step explanation:

Given :-

In ∆ABC, AD bisects interior ∠A and AE bisects exterior ∠A meeting BC at D and BC produced in E.

To prove:- BD/BE = CD/CE

Proof:-

In ∆ABC, AD bisects interior ∠A ( Given )

∴ AB/AC = BD/DC (Angle bisector theorem) .___(1)

Similarly in ∆ABC, AE bisects exterior ∠A ( Given )

∴ AB/AC = BE/CE .____(2)

Therefore, From eq. (1) and (2)

AB/AC = BD/DC = BE/CE = CD/CE

Thus, BD/BE = CD/CE

Hence proved.

Answer 2

Answer:

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