prove the identity tan²A + 1 = sec²A (4 marks)
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tan²A+1=sec²A
taking LHS
tan²A+1
tanA=sinA/cosA
so, using this...
sin²A/cos²A+1
(sin²A+cos²A)/cos²A
(sin²A+cos²A=1)
1/cos²A
sec²A
hence, LHS=RHS.....
taking LHS
tan²A+1
tanA=sinA/cosA
so, using this...
sin²A/cos²A+1
(sin²A+cos²A)/cos²A
(sin²A+cos²A=1)
1/cos²A
sec²A
hence, LHS=RHS.....
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