prove the result angle opp to equal sides of an iso triangles are equal
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Answered by
8
let ABC be an isosceles triangle and AD be the median,
then
we have two triangles,
∆ABD and ∆ACD,
now in ∆ABD and ∆ACD,
AB=AC (since ∆ is isosceles),
AD=AD (median),
BD=CD (since median bisect the side)
therefore by SSS congruence rule both the triangles are congruence,
hence
angle ABD = angle ACD (BY CPCT)
then
we have two triangles,
∆ABD and ∆ACD,
now in ∆ABD and ∆ACD,
AB=AC (since ∆ is isosceles),
AD=AD (median),
BD=CD (since median bisect the side)
therefore by SSS congruence rule both the triangles are congruence,
hence
angle ABD = angle ACD (BY CPCT)
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6
this is the answer.............
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