Question

Prove the sum of opposite angles of a cyclic quad is 180°

Answer 1

Answer:

Step-by-step explanation:

Answer 2

 Given : Let ABCD is cyclic quadrilateral. To prove : ∠A + ∠C = 180°  and ∠B + ∠D = 180°. Construction : join OB and OD. Proof : ∠BOD = 2 ∠BAD      ∠BAD = 1/2∠ BODSimilarly ∠BCD = 1/2 ∠DOB ∠BAD + ∠BCD = 1/2∠BOD + 1/2 ∠DOB                    =1/2(∠ BOD + ∠DOB)                    = (1/2)X360° = 180° Similarly ∠B + ∠D = 180°