prove this AP. (class 10 maths)
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If nth term=a+nb
for,
n=1;AP=a+b-------(1)
n=2;AP=a+2b-------(2)
n=3;AP=a+3b and so on....
now eqn2-eqn1
we get , b as common difference
Hence they are always in AP
for,
n=1;AP=a+b-------(1)
n=2;AP=a+2b-------(2)
n=3;AP=a+3b and so on....
now eqn2-eqn1
we get , b as common difference
Hence they are always in AP
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